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From the observation deck of a skyscraper, Meena measures a 48∘ angle of depression to a ship in the harbor below. If the observation deck is 1068 feet high, what is the horizontal distance from the base of the skyscraper out to the ship? Round your answer to the nearest tenth of a foot if necessary.

Respuesta :

Using the slope concept, it is found that the horizontal distance from the base of the skyscraper out to the ship is of 961.6 feet.

What is a slope?

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem:

  • The angle is of 48º.
  • The vertical change is of 1068 ft.
  • The horizontal change is of x.

Hence:

[tex]\tan{48^\circ} = \frac{1068}{x}[/tex]

[tex]x = \frac{1068}{\tan{48^\circ}}[/tex]

x = 961.6

The horizontal distance from the base of the skyscraper out to the ship is of 961.6 feet.

More can be learned about the slope concept at https://brainly.com/question/18090623

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