Well, at first consider the given equation, then will be solving for Part A) and B),
[tex]{:\implies \quad \sf 5+x-14=x-7}[/tex]
Subtracting x from both sides will yield ;
[tex]{:\implies \quad \sf 5-14=-7}[/tex]
[tex]{:\implies \quad \sf -9=-7}[/tex]
But, -9 ≠ -7, so their is no solution for values of x, as -9 can't be equal to -7 , so from definition of algebra, we can say that, their are no solutions for x, as there are no solutions for x, so nothing can be concluded from Part A and Part B