[tex]\sf\huge\underline{\star Solution:-}[/tex]
[tex]\rightarrow[/tex] Ratio of two angles are 6:13.
So, let the one angle be [tex]\sf{6x}[/tex] and another be [tex]\sf{13x.}[/tex]
As we know that,
Sum of all interior angles of a quadrilateral = [tex]\sf\pink{360°.}[/tex]
So let's sum up the given angles,
[tex]\rightarrow[/tex] [tex]\sf{222°+81°+6x+13x \:=\: 360°}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{303+19x \:=\: 360°}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{19x \:=\: 360-303}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{19x \:=\: 57}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{x \:=\: \frac{19}{57}}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{x \:=\: 3}[/tex]
Hence, [tex]\sf{x \:=\: 3}[/tex]
So, First angle [tex]\sf{= \:6x\: = \:6×3 \:=}[/tex] [tex]\sf\purple{18°.}[/tex]
Second angle [tex]\sf{= \:13x\: = \:13×3 \:=}[/tex] [tex]\sf\purple{39°.}[/tex]
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Hope it helps you:)
