Cut the square in half and use pythagorean thereom to solve for the long side of the triangle or it’s diameter.
a^2 + b^2 = c^2
8^2 + 8^2 = c^2
64 + 64 = c^2
128 = c^2 …square root both sides
c = 11.3137 (diameter)
radius is half diameter
r = 5.6569
Then you can subtract the area of a square a=bh from the area of the circle a = pi(r)^2.
a = (8)(8) the square’s area is 64.
a = pi (5.6569)^2
a = pi (32) the circle’s area is 32pi
so subtracting the area of the square from the circle is 32pi - 64.
Therefore it is the last selection 32pi - 64.
