A water balloon is launched in the air from a height of 12 feet and reaches a maximum height of 37 feet after 1.25 seconds. Write an equation to represent the height h of the water balloon at time t seconds. Then, find the height of the balloon at 2 seconds.

Respuesta :

The height of the balloon is given as h(t) = -16t² + 40t + 12 at 2 seconds, the height is 28 feet

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let h represent the height of the water balloon after t minutes, hence:

h(t) = -16t² + vt + h₀

Where h₀ is the initial height = 12 feet and v is the initial velocity, hence:

h(t) = -16t² + vt + 12

The height of 37 feet after 1.25 seconds, hence:

37 = -16(1.25)² + v(1.25) + 12

v = 40 m/s

h(t) = -16t² + 40t + 12

After 2 seconds:

h(t) = -16(2)² + 40(2) + 12

h(2) = 28 feet

The height of the balloon at 2 seconds is 28 feet

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