sketchisweird303
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Emily and Jennifer are playing a game with dice. Each one has a die. If each one rolls one and the sum of the numbers are 7 or 11 they win. If the sum is 2, 3 or 12 they lose. If it is any other number there is no winner or loser.

Find the sample space by either creating a tree or a chart/table. (remember, each die has the numbers 1-6 on it).


Then find:
P (they win - if the sum is 7 or 11)
P (they lose - if the sum is 2, 3 or 12)
The total sample space. HINT: How many total possible combinations?

Respuesta :

facundo3141592

This experiment has 36 possible combinations, and we will see that:

  • P(they win) = 0.22
  • P(they loose) = 0.11

How to get the probabilities?

First, we need to find the total number of outcomes.

We have two dice with 6 outcomes each, so the total number of outcomes of the experiment of tossing the two dice is:

C = 6*6 = 36

Such that the sample space is all the numbers between 2 and 12 (because our variable is the sum of the two values).

Now, to get the probability of winning we need to count the number of outcomes that add to 7 or 11, these are:

(Add to 7)

dice 1    dice 2            

   1            6                  

  2            5                  

   6           1

   5            2

    4           3

    3            4

(Add to 11)

dice 1    dice 2          

  5            6

  6             5

So there are 8 outcomes, then the probability of winning is:

P = 8/36  =0.22

The probability of losing is when the sum adds to 2, 3, or 12.

The outcomes that add to that:

(Add to 2)

dice 1    dice 2    

1               1

(Add to 3)

dice 1    dice 2    

 1              2

 2              1

(Add to 12)

dice 1    dice 2    

  6            6

There are 4 outcomes that add to these values, so the probability of losing is:

P = 4/36 = 0.11

If you want to learn more about probability, you can read:

https://brainly.com/question/251701

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