sketchisweird303
contestada

Emily and Jennifer are playing a game with dice. Each one has a die. If each one rolls one and the sum of the numbers are 7 or 11 they win. If the sum is 2, 3 or 12 they lose. If it is any other number there is no winner or loser.
Find the sample space by either creating a tree or a chart/table. (remember, each die has the numbers 1-6 on it).
Then find:
P (they win - if the sum is 7 or 11)
P (they lose - if the sum is 2, 3 or 12)
The total sample space. HINT: How many total possible combinations?

wrong answers and links will be reported. /srs

Respuesta :

For 7 or 11

  • S={(1,6),(2,5),(5,2),(6,1),(3,4),(4,3),(6,5),(5,6)}

For 2,3 and 12

  • S={(1,1),(1,2),(2,1),(6,6)}

Total:-

8 elements in sample space

semsee45

Answer:

**Please see attached for the sample space**

  • The winning combinations are highlighted in green.
  • The losing combinations are highlighted in red.

From inspection of the sample space:

  • Total number of ways the sum is 7 or 11 (win) = 8
  • Total number of ways the sum is 2, 3 or 12 (lose) = 4
  • Total number of possible outcomes = 36

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

[tex]\sf \implies P(win)= \dfrac{8}{36}=\dfrac29[/tex]

[tex]\sf \implies P(lose)= \dfrac{4}{36}=\dfrac19[/tex]

Ver imagen semsee45

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