The frequency of the recessive allele for the left handle will be in this case equal to q^2 = 0.25 >> q = 0.5.
The Hardy Weinberg principle is a model used in population genetics to estimate genotypic and allele frequencies.
The Hardy Weinberg principle states that the sum of the dominant allele and the recessive allele in a population is equal to 1 (p + q = 1).
This principle also states p2 + q2 + 2pq = 1, where p^2 is the dominant homo-zygous allele, 2pq the heterozygous frequency and q^2 the recessive homo-zygous frequency.
In this case, 9 individuals represent 25% (q^2 = 0.25), thereby the feecuency of q is equal to √0.25 = 0.5.
Learn more about the HW principle here:
https://brainly.com/question/1365714
