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A piece of iron is heated to 120'C then placed in a calorimeter containing 50g of water. The water temperature is raised from 30°C to 40°C. Assuming the specific heat of water is 4. 18 J/8'C and the specific heat of

Iron is 0. 44 J/g C, what is the mass of the piece of iron?

118. 8

59. 45

39. 6

752

Respuesta :

Answer:

Mass of iron = 59.375 gm

Explanation:

Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C

 The water gains:

     4.18  j/g-C  * 50 * (40-30 C) = 2090 j

The steel gave up 2090 j going from 120 to 40 C

2090 = .44 j/g-C  * m * (120-40)    solve fro m = 59.375 gm

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