The magnitude of the electric field at the given point is 8.33 * 10⁵N/C.
Given the data in the question;
The magnitude of electric field is simply referred to as the force per charge on a test charge.
It is expressed as;
[tex]E = \frac{F}{q}[/tex]
Here, F is electrostatic force exerted and q is the charge.
To determine the magnitude of the electric field at the given point, we substitute our given values into the expression above.
[tex]E = \frac{F}{q} \\\\E = \frac{5N}{6*10^{-6}C} \\\\E = 8.33 * 10^5N/C[/tex]
Therefore, the magnitude of the electric field at the given point is 8.33 * 10⁵N/C.
Learn more about coulomb's law: brainly.com/question/506926
