By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
Distance between q₂ and q₃
The distance between the second charge and the third charge is given as;
r = 0.3 m
Force on q₂ due to q₃
[tex]F_{2} = \frac{kq_2q_3}{r^2} \\\\F_{2}= \frac{(8.99\times10^9) (7.7 \times 10^{-6})(5.9\times 10^{-6}) }{0.3^2} \\\\F_2 = 4.54\ N[/tex]
Net force on particle q₁
The net force on particle q₁ is determined by summing the individual forces together;
F(net) = F₁ + F₂
F(net) = -14.4 + 4.54
F(net) = -9.86 N
Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
Learn more about Coulomb's law here: https://brainly.com/question/24743340
