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Many cigarette lighters contain liquid butane, C4H10, which has a ∆H°ƒ = –147.6 kJ/mol. Using enthalpies of formation, calculate the quantity of heat produced when 1.0 g of butane is completely combusted in air. (Write the equation for the process first)

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For cigarette lighters containing liquid butane, C4H10, the quantity of heat produced  is mathematically given as

q= -49.2 KJ

What is the quantity of heat produced when 1.0 g of butane is completely combusted in air?

Generally, the equation for the Chemical reaction   is mathematically given as

C₄H₁₀(l) + 6.5 O₂(g)---->4 CO₂(g) + 5 H₂O(l)

Therefore

dH°r = .(-393.5 ) + 5.(-285.5] - [1.(-147.6 )+6.5.

dH°r = -2853.9 kJ/mol

In conclusion, No.of mole

Nm = 1g/58g/mol

Nm= 0.01724mol

Hence, Heat of combustion

q = dH°r x moles

q = -2853.9 ×0.01724

q= -49.2 KJ

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