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The pH of a solution prepared by dissolving 0. 350 mol of solid methylamine hydrochloride (CH3NH3Cl) in 1. 00 L of 1. 10 M methylamine (CH3NH2) is ________. The Kb for methylamine is 4. 40 ⋅ 10-4. (Assume the final volume is 1. 00 L. )

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okpalawalter8

For the pH of a solution prepared by dissolving 0. 350 mol of solid methylamine hydrochloride, the pH is mathematically given as

pH = 11.14

What is the pH value of a solution prepared by dissolving 0. 350 mol ?

Generally, the equation for the pKb  is mathematically given as

pKb = -logKb

Therefore

pKb of CH3NH2 = -log(4.40×10-4)

pKb of CH3NH2= 3.36

Hence

pKa= 14 - pKb

pKa= 14 - 3.36

pKa= 10.64

In conclusion, using

pH = pKa + log([A-]/[HA])

pH = 10.64 + log(1.10M/0.350M)

pH = 11.14

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