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The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in slope-intercept form.

Respuesta :

Answer:

y=-5x-2

Solution:

  • We are given the line's slope and a point that it passes through.
  • Using the given information, we can write the equation of the line in Point-Slope Form:
  • [tex]y-y_1=m(x-x_1)[/tex]
  • In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
  • In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
  • Plug in the values:
  • y-(-12)=-5(x-2)
  • y+12=-5(x-2)
  • Now, convert into Slope-Intercept Form, y=mx+b:
  • y+12=-5x+10
  • y=-5x+10-12
  • y=-5x-2

Hope it helps.

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