Using the expected value of a discrete distribution, it is found that:
a) His expected value is of -$2.5.
b) The fair price of a ticket is of $0.5.
The expected value of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
In this problem, the distribution for the net value of the ticket is:
Item a:
The expected value is given by:
[tex]E(X) = 497\frac{1}{1000} - 3\frac{999}{1000} = -2.5[/tex]
His expected value is of -$2.5.
Item b:
With an unknown ticket price, the distribution is:
The game is fair if E(X) = 0, hence:
[tex]\frac{500 - x}{1000} - \frac{999x}{1000} = 0[/tex]
0.5 - x = 0
x = 0.
The fair price of a ticket is of $0.5.
More can be learned about the expected value of a discrete distribution at https://brainly.com/question/24855677