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What is the equivalent resistance of a circut that contains two 50.0 resistors connects in parellels with a 12.0 V battery?

o A. 25.0
o B. 0.040
o C. 100.0
o D. 0.48

Respuesta :

Answer:

1/Re=1/R1  +1/R2= 2x1/R1=2/R1=2/R2=2/50=1/25

1/Re=1/25, so the answer is Re= 25

the answer is A. 25.0

Answer:

A. 25.0

Explanation:

1/Re = 1/R1 + 1/R2 = 2 x 1/R1 = 2/R1 = 2/R2 = 2/50 = 1/251/Re = 1/25
The answer is Re= 25


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