Answer:
T9 = 5/256
Step-by-step explanation:
You can tell it by looking at the pattern of the progression whether each term +- or ×÷.
From the question,
First term, a = 5
Common ratio, r = (5/2)/5 = ½
n = 9
Using the formula for nth term of a geometric progression,
[tex] t_{n} = a {r}^{n - 1} [/tex]
T9 = 5(½)^(9-1)
= 5/256