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Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.
6 9

Find the Area of the figure below composed of a rectangle and a semicircle Round to the nearest tenth place 6 9 class=

Respuesta :

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

[tex]Area=\pi r^2/2[/tex]

[tex]Area=\pi (3)^2/2=9\pi /2[/tex]

The area of a rectangle is the length multiplied by the width:

[tex]Area=l*w[/tex]

[tex]Area=6*9=54[/tex]

The net area is the sum of the rectangle and the semi-circle:

[tex]Area=(9\pi /2)+(54)=68.1[/tex]

For rectangle

Area:-

  • Length ×Breadth
  • 9(6)
  • 54units^2

For semicircle

  • Radius=6/2=3

Area:

  • πr^2/2
  • 9π/2
  • 4.5π
  • 14.13units^2

Total:-

  • 54+14.13
  • 68.13units^2