casrdunn8765 casrdunn8765

15-03-2022
Chemistry

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A balloon that had a volume of 3. 50 L at 25. 0°C is placed in a hot room at 40. 0°C. If the pressure remains constant at 1. 00 atm, what is the new volume of the balloon in the hot room?.

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safkathjahan12 safkathjahan12

15-03-2022

Ans : 3.33L

Solution:

V1/T1 = V2/T2
So, T2 = V2*T1/V1 = (3.50* 298)/313 = 3.33L

Here V1 = 3.50 L T1 = 25 degree C = 25+273 K =298 K
T2= 40 degree Celsius = 40+ 273 = 313K

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