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In a specific species of frog, the allele for green coloration is dominant over the allele for brown skin coloration. The original population contains 28 HH frogs, 52 Hh frogs, and 20 hh frogs.

At the start of the experiment, the researchers remove all hh frogs from the population.
Calculate the frequency of the recessive allele in the remaining population.

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Based on the data provided and the Hardy-Weinberg equilibrium equation, the frequency of the recessive allele in the population is 0.53.

How can the allele frequency be determined?

The allele frequency can be calculated from the Hardy-Weinberg equilibrium equation.

The Hardy-Weinberg equilibrium equation is given as:

  • p^2 + 2pq + q^2 = 1 and
  • p + q = 1

where:

  • p = frequency of the dominant allele in the population
  • q = frequency of the recessive allele in the population
  • p2 = percentage of hom0zygous dominant individuals
  • q2 = percentage of hom0zygous recessive individuals
  • 2pq = percentage of heterozygous individuals

Total population of frogs = 100

percentage of hom0zygous recessive individuals, q^2 = 28/100 = 28%

Frequency of the recessive allele in the population is calculated as:

[tex]q = \sqrt{ {q}^{2} } [/tex]

[tex]q = \sqrt{0.28} [/tex]

q = 0.53

Therefore, frequency of the recessive allele in the population is 0.53.

Learn more about allele frequency at: https://brainly.com/question/4393505

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