Respuesta :

hamzaahmeds

This question involves the concepts of electric potential, charge, and distance.

The electric potential is "48 V".

ELECTRIC POTENTIAL

The electric potential of a point in the vicinity of a charge is given by the following formula:

[tex]V=\frac{kq}{r}[/tex]

where,

  • V = electric potential = ?
  • k = Colomb's constant = 9 x 10⁹ N.m²/C²
  • q = magnitude of charge = 1.6 x 10⁻¹⁹ C
  • r = distance from charge = 3 x 10⁻¹¹ m

Therefore,

[tex]V = \frac{(9\ x\ 10^9\ Nm^2/C^2)(1.6\ x\ 10^{-19}\ C)}{3\ x\ 10^{-11}\ m}[/tex]

V = 48 volts

Learn more about the electric potential here:

https://brainly.com/question/9383604

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