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Identify the symmetrical interval that includes​ 95% of the sample means for a population with a mean equal to 44 and a standard deviation equal to 9 using a sample size of 36

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okpalawalter8

The symmetrical interval at Confidence interval 95% is mathematically given as

(42.06,47.94)

What is the symmetrical interval?

Question Parameters:

Confidence interval 95%

a mean equal to 44 and a standard deviation equal to 9 using a sample size of 36

Where

\alpha=1-95

\alpha/2=0.025

Generally, the equation for the Margin of error  is mathematically given as

M.E=Z_{\alpha/2} x\frac{\sigma}{\sqrt{n}}

Therefore

M.E=1.96\frac{9}{\sqrt{36}}

M.E=2.94

In conclusion, at a Confidence interval 95% the symmetrical interval is

45-299<u<\=x+E

(42.06,47.94)

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