The electric potential energy of a charge that experiences a force of 3. 6 × 10⁻⁴ N when it is 9. 8 × 10⁺⁵m from the source of the electric field will be 3.528×10⁻⁸ V.
Electric potential energy is the amount of work needed to move a unit charge from a point to a specific point against an electric field.
The given data in the problem is;
F is the electric force= 3. 6 × 10⁻⁴ N
V is the electric potential=?
d is the distance = 9. 8 × 10⁻⁵ m
The electric potential energy is given as the product of the electric force and distance.
V=Fd
V = 3.6×10⁻⁴ ×( 9.8×10⁻⁵)
V = 3.528×10⁻⁸ V.
Hence the electric potential energy of a charge will be 3.528×10⁻⁸ V.
To learn more about electric potential energy refer to the link.
https://brainly.com/question/12707371
