The strength of the electric field will be 2.8×10⁵ NC⁻¹. Electric force F acted per unit positive electric charge q is known as the electric field strength.
The electric, or Coulomb, forces exerted per unit positive electric charge q at any place, can be used to calculate the strength of an electric field E at any position.
It is given by;
E = F/q
The given data in the problem is;
q is the value of charge=6. 4 × 10⁻C
F is the electric force = 1.8 × 10⁻¹ N
E is the electric field strength =?
The electric field strength is found by the formula;
[tex]\rm E=\frac{F}{q} \\\\ \rm E=\frac{6.4\times 10^{-7}}{1.8 \times 10^-1} \\\\ \rm E= 2.8 \times 10^5 \ N/C[/tex]
Hence the electric field strength will be 2.8×10⁵ NC⁻¹.
To learn more about the electric field strength refer to the link;
brainly.com/question/4264413
