Bearing........find the marked angles f and g
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Answer:
Step-by-step explanation:
g is a central angle for arc PQ
= 2 * segment angle of arc PQ
= 2 * <PRQ
= 2 * (180 - 114)
= 2 * 66
= 132 degree
Drawing is a little confusing about f and assuming f is <PQO
<PQO = <QPO because OPQ is an isosceles triangle
The sum of interior angles of a triangle = 180 degree
f + f + g = 180
2f = 180 - 132 = 48
f = 24 degree
Edit: Thank you, fieryanswererft, for pointing out my mistake!
Answer:
g = 132° , f = 24°
Step-by-step explanation:
∠ PRQ = 180° - 114° = 66°
the central angle g is twice the angle subtended at the circumference on the same arc PQ , then
g = 2 × ∠ PRQ = 2 × 66 = 132°
Δ POQ is isosceles , 2 congruent sides , the radii OP and OQ
The base angles of the triangle are congruent , then
f = [tex]\frac{180-132}{2}[/tex] = [tex]\frac{48}{2}[/tex] = 24°