Step-by-step explanation:
Roots Theorem
[tex]6 {x}^{2} + 11x - 10 = 0[/tex]
Use the AC method,
The roots must multiply to -60 and add up to 11.
Those two numbers are 15 and -4
So we have know
[tex]6 {x}^{2} + 15x - 4x - 10 = 0[/tex]
[tex]3x(2x + 5) - 2(2x + 5)[/tex]
[tex](3x - 2)(2x + 5) = 0[/tex]
Set each binomial equal to zero
[tex]3x - 2 = 0[/tex]
[tex]3x = 2[/tex]
[tex]x = \frac{2}{3} [/tex]
[tex]2x + 5 = 0[/tex]
[tex]2x = - 5[/tex]
[tex]x = - \frac{5}{2} [/tex]
