Answer:
x = 0, y = -3/2
Step-by-step explanation:
Solve the following system:
{-2 y + x = 3 | (equation 1)
{-8 y + 14 x = 12 | (equation 2)
Swap equation 1 with equation 2:
{14 x - 8 y = 12 | (equation 1)
{x - 2 y = 3 | (equation 2)
Subtract 1/14 × (equation 1) from equation 2:
{14 x - 8 y = 12 | (equation 1)
{0 x - (10 y)/7 = 15/7 | (equation 2)
Divide equation 1 by 2:
{7 x - 4 y = 6 | (equation 1)
{0 x - (10 y)/7 = 15/7 | (equation 2)
Multiply equation 2 by 7/5:
{7 x - 4 y = 6 | (equation 1)
{0 x - 2 y = 3 | (equation 2)
Divide equation 2 by -2:
{7 x - 4 y = 6 | (equation 1)
v0 x+y = -3/2 | (equation 2)
Add 4 × (equation 2) to equation 1:
{7 x+0 y = 0 | (equation 1)
{0 x+y = -3/2 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 0 | (equation 1)
{0 x+y = -3/2 | (equation 2)
Collect results:
Answer: x = 0, y = -3/2
