With the compounds sample mass at 150g, and we are left to decipher the proportion of Carbon, Hydrogen, and Oxygen amount, The compound's empirical formula is mathematically given as
Ep=C5H12O4
What is the compound's empirical formula?
Question Parameters:
A 150 g sample of a compound is comprised of 44.07% C, 8.98% H and the remainder is O by mass
Generally, the equation for the compound is mathematically given as
CxHyOz
Where
Therefore
O percentage is
Po100-(44.07+8.98)
Po=46.95
For Cx we determine the minimum value
hence
x=1.25*4
x=5
For Hy
y=3.0*4
For Oz
y= 1*4
y=4
In conclusion, the empirical formula is
C5H12O4
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