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A. Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL.

B. How many moles of sodium are in the solution

Respuesta :

Eduard22sly

A. The molarity of solution containing 5.2 g of sodium sulphate is 0.0732 M

B. The number of mole of sodium in the solution is 0.0732 mole

How to determine the mole of sodium sulphate Na₂SO₄

  • Mass of Na₂SO₄ = 5.2 g
  • Molar mass of Na₂SO₄ = (23×2) + 32 + (16×4) = 142 g/mol
  • Mole of Na₂SO₄ =?

Mole = mass / molar mass

Mole of Na₂SO₄ = 5.2 / 142

Mole of Na₂SO₄ = 0.0366 mole

A. How to determine the molarity

  • Mole of Na₂SO₄ = 0.0366 mole
  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 0.0366 / 0.5

Molarity = 0.0732 M

B. How to determine the mole of sodium (Na)

1 mole of Na₂SO₄ contains 2 moles of Na.

Therefore,

0.0366 mole of Na₂SO₄ will contain = 0.0366 × 2 = 0.0732 mole of Na

Thus, 0.0732 mole of Na is present in the solution.

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