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A system consists of a disk rotating on a frictionless axle and a piece of clay moving toward it, as shown in the figure above. The outside edge of the disk is moving at a linear speed v, and the clay is moving at speed v/2. The clay sticks to the outside edge of the disk. How does the angular momentum of the system after the clay sticks compare to the angular momentum of the system before the clay sticks, and what is an explanation for the comparison?.

Respuesta :

daniilrocks987

Explanation:

Forgive me If I am wrong, it's been a while since I've studied Torque.

The formula for the angular momentum is

momentum= I*w.

We can also write I*W as 1/2MR^2 * W so the extra mass coming from the block of clay would most likely cause the angular momentum to increase from the amount it was before.

onyebuchinnaji

The angular momentum of the system before and after the clay sticks will be the same.

Conservation of angular momentum

The principle of conservation of angular momentum states that the total angular momentum is always conserved.

Li = Lf

Iiωi = Ifωf

where;

  • Ii is the initial moment of inertia
  • If is the final moment of inertia
  • ωi is the initial angular velocity
  • ωf is the final angular velocity
  • Li is the initial angular momentum
  • Lf is the final angular momentum

Thus, the angular momentum of the system before and after the clay sticks will be the same.

Learn more about angular momentum here: https://brainly.com/question/7538238

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