The enthalpy change involved in the dissolution of 17. 5 grams of NH₄NO₃ in water is +5.47 KJ
1 mole of NH₄NO₃ = 14 + (1×4) + 14 + (3×16) = 80 g
Thus, we can say that:
80 g of NH₄NO₃ has an enthalpy change of +25 KJ
Therefore,
17.5 g of NH₄NO₃ will have an enthalpy change of = (17.5 × 25) / 80 = +5.47 KJ
Thus, the enthalpy change for 17.5 g of NH₄NO₃ is +5.47 KJ
Learn more about enthalpy change:
https://brainly.com/question/11967318