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If you are given the graph of h (x) = log subscript 6 baseline x, how could you graph m (x) = log subscript 6 baseline (x + 3)? translate each point of the graph of h(x) 3 units up. Translate each point of the graph of h(x) 3 units down. Translate each point of the graph of h(x) 3 units right. Translate each point of the graph of h(x) 3 units left

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Answer:

D on edge

Explanation:

i saw the answer on another site

The method of graphing m(x) = log₆(x + 3) is; by translating each point of the graph of the function h(x) 3 units to the left.

How to Translate Functions?

The function we are given is; h(x) = log₆x

From the given function, we notice that the function m(x) is the function h(x). However, it is shifted 3 units to the left.

Thus, it means that we could graph the function m(x) by translating each point of the graph of the function h(x) 3 units to the left.

Thus, the conclusion of this method of graphing m(x) = log₆(x + 3) is by translating each point of the graph of the function h(x) 3 units to the left.

Read more about Function Translations at; https://brainly.com/question/26238840

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