Based on the calculations, we have the following:
Given the following data:
Mathematically, the area of the paper is given by this formula:
[tex]Area = length \times breadth\\\\Area = 12 \times 8[/tex]
Area = 96 square inches.
For the four (4) right triangles:
Therefore, the combined area of the triangle cutouts is given by:
[tex]A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2[/tex]
This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:
[tex]P = A_p -A_2\\\\P=96-36[/tex]
P = 60 square inches.
[tex]P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}[/tex]
Altitude = 6.51 square inches.
Read more on parallelogram here: https://brainly.com/question/4459854
Complete Question:
A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.
