The electric field strength is defined as the ratio of electric force and charge. The electric field strength will be 2.8 ×10⁵ N/C.
The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.
A positive charge produces a radially outward electric field, whereas a negative charge produces a radially inward electric field.
The given data in the problem is;
Q is the charge= 6. 4 × 10–7 C
E is the electric force=1. 8 × 10–1 N
The relation between the electrostatic force and the electric field due to a charge is given as:
[tex]\rm F_E=Q E \\\\ \rm E=\frac{F_E}{Q} \\\\ \rm E=\frac{1.8\times 10^{-1}}{6.4\times 10^{-7}} \\\\ \rm E=2. 8 \times 10^5\ N/C.[/tex]
Hence the electric field strength will be 2.8 ×10⁵ N/C.
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