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Point B on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions
per second is located 0.20 m from the axis of rotation. Pont A is just at the border
of the wheel. See the figure.

a) What is the angular velocity of the wheel in rad/s?

b) What point has a greater linear speed, A or B? Calculate both speeds and
compare the results.

c) What are the centripetal accelerations of points A and B due to the spin of the
wheel? Sketch the situation and represent the vectors linear velocity and
centripetal acceleration in points A and B. Assume the rotation of the wheel
to be clockwise.

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onyebuchinnaji

(a) The angular velocity of the wheel is 31.42 rad/s.

(b) The linear speed of the wheel at point A is greater than point B.

(c) The centripetal accelerations of points A is 394.89 m/s² and point B is 197.44 m/s².

Angular velocity of the wheel

The angular velocity of the wheel is calculated as follows;

ω = 2π (5) = 31.42 rad/s

Linear speed of the wheel at point A

v = ωr

v = 31.42 x 0.4

v = 12.57 m/s

Linear speed of the wheel at point B

v = ωr

v = 31.42 x 0.2

v = 6.28 m/s

Thus, the linear speed of the wheel at point A is greater than point B.

Centripetal acceleration at point A

a = ω²r

a = (31.42)² x 0.4

a = 394.89 m/s²

Centripetal acceleration at point B

a = ω²r

a = (31.42)² x 0.2

a = 197.44 m/s²

Learn more about centripetal acceleration here: https://brainly.com/question/79801

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