The minimum amount of wrapping paper needed, in square feet, to wrap all 3 boxes is 12.5 square feet.
Side of each cube = 10 inches
Number of cubes =3
As we know The minimum amount of wrapping paper needed, in square feet, to wrap all 3 boxes will be the total surface area of all 3 boxes.
What is the total surface area of a cube?
The total surface area of a cube with side a is 6a².
So, the total surface area of a cube with a side of 10 inches will be 6*10² = 6*100 = 600 square feet.
So, the total surface area of 3 cubes with a side of 10 inches will be 600*3 = 1800 square inches.
As we know that 1 square inch = 0.00694444 square feet
So, 1800 square inches = 1800*0.00694444 = 12.5 square feet.
Therefore, the minimum amount of wrapping paper needed, in square feet, to wrap all 3 boxes is 12.5 square feet.
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