Please help!
A building is constructed on top of a cliff that is 300 meters high. A person standing on level ground below the cliff observes that the angle of elevation to the top of the building is 72° and the angle of elevation to the top of the cliff is 63°.

a. How far away is the person from the base of the cliff?

b. What is the building’s height?

Respuesta :

The distance from the person to the base of the cliff is 269.78 meters.

The height of the building from the base of the cliff is 829.37 meters

The situation forms right angle triangle.

The building is constructed on top the cliff that is 300 meters high.

Right angle triangle:

Right angle triangle has one of its sides as 90 degrees. Therefore, the sides can be found using trigonometric ratios.

The height of the building from the cliff is 300m. let's find the hypotenuse side of the angle of elevation formed to the cliff.

Using sin rule,

300 / sin (72 - 63) = y / sin (180 - 162)

300 / sin 9 = y / sin 18

300 sin 18 = y sin 9

y = 300 sin 18 / sin 9

y = 92.7050983125 / 0.156

y = 594.230769231

Therefore, how far the person to the base of the cliff can be calculated as follows;

cos 63 = adjacent / hypotenuse

cos 63 = x / 594.2307

x = 594.2307 cos 63

x = 269.775092454

x = 269.78 meters

Therefore, the distance from the person to the base of the cliff is 269.78 meters.

height of the cliff  / 269.78 = tan 63

height of cliff = 269.78 tan 63

height of cliff = 529.37493165

height of cliff = 529.37

The height of the building = 300 + 529.37 = 829.37493165 = 829.37 meters

learn more on right triangle here: https://brainly.com/question/14806301