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The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first base throws the ball to a player at third base, what is the distance the player has to throw? 90 feet is first base 90 feet at third base

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Answer:

ta side from one base to next has  length of x. so we know each side has length x and  the shape they make is a square. This means we are only searching for the diagonal of a square. remember that a diagonal forms and isoscoles right triangle with the 2 sides being equal and the diagonal as the hypotenuse. Using  pythagoream theorem we can say

a^2 + b^2 = c^2 all side lengths are x so we can put x in for a and b  to get

x^2 + x^2 = c^2

2x^2 = c^2

c = x * squareroot(2)

so if the length between bases is 90 ft

c = 90 ft * squareroot(2)

c = 127.28 ft

Step-by-step explanation:

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