so when we add to the function outside of the parentheses of (x)^3, we are moving the graph in the up down direction so it would look like x^3 but shifted up 2 units. the way to easily know which one it is, plug in zero for x in the original and 0^3 is zero so we know the original fuction will go through the origin so the function who's center is is only shifted up (because it's positive 2) two units so graph 1
note: the reason i know that what looks like a center point is actually at the origin is because f(x)= x^3 is a very famous graph that you should know the shape of :)
