Respuesta :
Answer:
The length scale factor = \(\frac{24}{6} = 4\)
The area scale factor = \(4^2 = 16\)
\[\text{Larger area} = 16 \times \text{smaller area}\]
\[50.3 \times 16 = 804.8\]
The area of the large clock face is approximately 804.8 cm2.
Step-by-step explanation:
The length scale factor = \(\frac{24}{6} = 4\)
The area scale factor = \(4^2 = 16\)
\[\text{Larger area} = 16 \times \text{smaller area}\]
\[50.3 \times 16 = 804.8\]
The area of the large clock face is approximately 804.8 cm2.
Answer:
a) the linear scale factor = 5/3
b) the volume scale factor = 125/27
c) 70.2 cm³
Step-by-step explanation:
r₁ = 15 cm, r₂ = 25 cm
r₂/r₁ = 25/15 = 5/3
They are similar, so h₂/h₁ = 5/3
a) the linear scale factor = 5/3
b) the volume scale factor = (5/3)³ = 125/27
c) V₂/V₁ = 125/27
Given V₂ = 325 cm³, V₁ = 325*27/125 = 70.2 cm³