PLEASE HELP ME WITH THIS QUESTION
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Answer:
x = 2√58
Step-by-step explanation:
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs and c is the hypotenuse of a right triangle)
Find the height of the triangle by using the base and hypotenuse of the smaller interior triangle and Pythagoras' Theorem:
a² + b² = c²
⇒ a² + 6² = (6√2)²
⇒ a² = (6√2)² - 6²
⇒ a² = 36
⇒ a = 6
Now we have the base and height of the larger interior triangle, we can calculate x:
a² + b² = c²
⇒ 6² + 14² = x²
⇒ x² = 232
⇒ x = √232
⇒ x = 2√58
[tex]\\ \rm\Rrightarrow \dfrac{6\sqrt{2}}{6}=\dfrac{x}{14}[/tex]
[tex]\\ \rm\Rrightarrow 6x=84\sqrt{2}[/tex]
[tex]\\ \rm\Rrightarrow x=14\sqrt{2}[/tex]