Respuesta :

The relativistic momentum of the rocket differ from the ordinary momentum by a factor of 1.2m.

Relativistic momentum of the rocket

The relativistic momentum of the rocket is calculated as follows;

[tex]P = \frac{mv}{\sqrt{1- \frac{v^2}{c^2} } } \\\\P = \frac{m(12010)}{\sqrt{1- \frac{(12010)^2}{(3\times 10^8)^2} } } \\\\P = 12,011.2 m \ (kgm/s)[/tex]

where;

  • m is mass of the rocket

Ordinary momentum of the rocket

The ordinary momentum of the rock is calculated from the product of mass and velocity of the rocket.

P = mv

P = 12010m (kgm/s)

Difference between the two momentum

ΔP = 12,011.2m - 12,010m

ΔP =  1.2m

Thus, the relativistic momentum of the rocket differ from the ordinary momentum by a factor of 1.2m.

Learn more about relativistic momentum here: https://brainly.com/question/9864983