Belmont is a growing industrial town. Every year, the level of CO2 emissions from the town increases by 10%. If the town produced 330,000 metric tons of CO2 this year, how much will be produced 6 years in the future? If necessary, round your answer to the nearest whole number

Belmont will produce 584,615 metric tons of CO₂ after 6 years, growing at the rate of 10% every year, currently emitting 330,000 metric tons of CO₂.

What do we mean by growth?

The value of most things is not constant in this world. If we observe correctly, the value of some of the things rises, while others fall. If there is a rise, we call it growth.

Growth can be determined by the formula,

V = V₀(1+r)ⁿ, where V is the final value, V₀ is the initial value, r is the rate and n is the time.

How do we solve the given question?

In the question, we are given that Belmont is a growing industrial town. Every year, the level of CO2 emissions from the town increases by 10%.

We are asked that if the town produced 330,000 metric tons of CO2 this year, how much will be produced 6 years in the future.

As we see that the amount of CO₂ emission is growing, to find the amount of CO₂ emitted in the 6th year, we use the growth formula,

V = V₀(1+r)ⁿ, where V is the final value, V₀ is initial value, r is rate, and n is the time period.

Here, V₀ = 330,000 metric tons, r = 10%, n = 6 years.

∴ V = 330,000(1 + 10%)⁶

or, V = 330,000(1.1)⁶ = 330,000*1.771561 = 548615.13

or, V = 548615 metric tons (rounded to nearest whole number).

∴ Belmont will produce 584,615 metric tons of CO₂ after 6 years, growing at the rate of 10% every year, currently emitting 330,000 metric tons of CO₂.

Learn more about Growth at

https://brainly.com/question/20115298

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