Respuesta :
Answer:
Option C .
Step-by-step explanation:
Here it is given that there are two species of birds which fly at different rates.
- Species A can fly 18.9 miles in 42min .
- Species B can fly 20.3miles in 59min .
We can use the formula here ,
[tex]\longrightarrow \red{ Speed =\dfrac{Distance} {Time} }[/tex]
For Species A :-
Substitute the respective values in stated formula ,
[tex]\longrightarrow v_A = \dfrac{18.9\ miles}{42min}\\[/tex]
Simplify ,
[tex]\longrightarrow v_A = 0.45\ miles / min [/tex]
For species B :-
Substitute the respective values in stated formula,
[tex]\longrightarrow v_B =\dfrac{20.3\ miles}{58min}\\ [/tex]
[tex]\longrightarrow v_B = 0.35\ miles / min [/tex]
Therefore from above calculations we can say that ,
[tex]\underline{\underline{ v_A > v_B }}[/tex]
Species B is slower and it can fly 0.35miles/minute .
Answer:
C is your answer your looking for
Step-by-step explanation:
i found it out becouse i did the answer today got it right its easy if you understand it