The minimum qualifying score to join the genius society is 130, the correct option is B.
In the top 2%, you have to have an IQ higher than 98% of the population (100% - 2%). This is also known as the 98th percentile.
Given
A genius society requires an IQ that is in the top 2% of the population in order to join.
If an IQ test has a mean of 100 and a standard deviation of 15.
For this problem, you are given the probability and need to determine the raw score.
For the probability, go to the z–table and find the probability that is closest to 0.98. Then look across the row and up the column to determine the z-score.
The closest probability is 0.97982 and that corresponds to a z-score of 2.05.
With a z-score of 2.05, you can use the z formula to compute the raw score.
[tex]\rm z-score=\dfrac{X- mean }{Standard \ deviation}\\\\2.05=\dfrac{x-100}{15}\\\\2.05 \times 15 = x-100\\\\30 +x-100\\\\x=100+30\\\\x = 130[/tex]
Hence, the minimum qualifying score to join the genius society is 130.
To know more about z-score click the link is given below.
https://brainly.com/question/13299273