Given that the amount of fiber in 100 grams of beans is 3.6 grams the amount of fiber consumed from [tex]\mathbf{\frac{2}{3}}[/tex] of the small tin is 4.8 grams.
How can the amount of fiber consumed be calculated?
From the given table, we have;
Mass of fiber in 100 g of beans = 3.6 grams
Mass of beans in the small tin = 200 grams
The quantity of the beans eaten = [tex]\frac{2}{3}[/tex] of the small tin
Required:
The amount of fiber to consumed from eating [tex]\frac{2}{3}[/tex] of the small tin
Solution;
[tex]Amount \ of \ fiber \ consumed = 200 \, g \times \dfrac{3.6 \, g}{100 \, g} \times \dfrac{2}{3} = \mathbf{4.8 \, g}[/tex]
Therefore;
The amount of fiber consumed by eating [tex]\frac{2}{3}[/tex] of the small tin = 4.8 grams
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