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A parallel plate capacitor has a potential difference between its plates of 1.6 V and a plate separation distance of 2.5 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.4 is inserted between the plates

Respuesta :

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(a) The magnitude of the electric field of the material is 600 V/m.

(b) The magnitude of the electric field of the material in the presence of dielectric constant is 176.5 V/m.

Electric field of the material

The magnitude of the electric field of the material is calculated as follows;

E = V/d

where;

  • E is the electric field
  • V is the potential difference between the plates
  • d is the distance of separation

Substitute the given parameter into the equation above.

E = 1.5/(2.5 x 10⁻³)

E = 600 V/m

Electric field in the presence of dielectric constant

E = E₀/k

E = 600/3.4

E = 176.5 V/m

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