Type the correct answer in the box. Express your answer to three significant figures. Sodium hydroxide and magnesium chloride react as shown by this equation: 2NaOH MgCl2 → Mg(OH)2 2NaCl. Suppose the reaction begins with 637 milliliters of 1. 35 M sodium hydroxide solution and excess magnesium hydroxide. What is the theoretical yield of magnesium hydroxide if the resulting solution has a volume of 2. 82 liters? Use the periodic table and the polyatomic ion resource. The mass of magnesium hydroxide formed is grams.

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nikitarahangdaleVT nikitarahangdaleVT · Answer 1 · 2022-03-16T14:02:10+01:00

25.07grams is the theoretical yield of magnesium hydroxide if the resulting solution has a volume of 2. 82 liters.

Mass of any substance will be calculated from moles as:

n = W/M, where

W = given or required mass

M = molar mass

Given chemical reaction is:

2NaOH + MgCl₂ → Mg(OH)₂ + 2NaCl

From the stoichiometry of the reaction, it is clear that:

2 moles of NaOH = produce 1 mole of Mg(OH)₂

1 mole of NaOH = produce 1/2 mole of Mg(OH)₂

Given concentration of NaOH = 1.35M

Given volume of NaOH = 637mL = 0.637L

Moles of NaOH will be calculated as:

M = n/V

n = 1.35M × 0.637L = 0.859 moles

So, 0.859 moles of NaOH = produce 0.859×1/2 = 0.429 moles of Mg(OH)₂

Now, we convert this moles into grams by using the above formula:

0.429 = W/58.31 g/mole

W = 25.07grams

Hence, 25.07grams is the theoretical yield of magnesium hydroxide.

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