Part A: What do the x-intercepts and maximum value of the graph represent in context of the described situation?
Part B: What are the intervals where the function is increasing and decreasing, and what do they represent about the sale and
profit for the company in the situation described?
Part C: What is an approximate average rate of change of the graph from x = 1 to x = 3, and what does this rate represent in
context of the described situation?

Part A What do the xintercepts and maximum value of the graph represent in context of the described situation Part B What are the intervals where the function i class=

Respuesta :

The x intercept of the given graph of the company's profit is where the curve of the graph crosses the x-axis.

How to determine the x-intercept

In this figure, the graph crosses the x-axis at x = 0 and x = 6

This represents the profit is 0 when the price is $0 and $6, respectively

The maximum value

This represents the maximum profit that can be made.

From the graph, the maximum profit is $120

The increasing and the decreasing interval

From the graph, the graph increases from x = 0 to x = x = 3, and it decreases from x = 3 to x = 6

These intervals represent when the profit increases, and when it decreases

The average rate of change

This is calculated as:

[tex]m = \frac{f(b) - f(a)}{b - a}[/tex]

So, we have:

[tex]m = \frac{f(3) - f(1)}{3 - 1}[/tex]

[tex]m = \frac{f(3) - f(1)}{2}[/tex]

Substitute known values

[tex]m = \frac{120 - 60}{2}[/tex]

[tex]m = \frac{60}{2}[/tex]

Simplify

[tex]m = 30[/tex]

Hence, the average rate of change from x = 1 to x = 3 is a profit of $30 per unit sale

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