Given the equation 2x = 4y - 3 write another linear equation that would create a system that has the number of solutions listed
A . 0 Solutions
B . 1 Solution
C . Infinitely many solutions

Respuesta :

Paounn

Answer:

A. [tex]2x-4y=\pi[/tex]
B.  [tex]x=1[/tex]

C. [tex]2x-4y=3[/tex]

Step-by-step explanation:

A. [tex]2x-4y=\pi[/tex]. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND [tex]\pi[/tex], or any number you like. But yesterday was 3/14 so let's pick a fun number!

B.  [tex]x=1[/tex] Or [tex]y=1[/tex]. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind

C. [tex]2x-4y=3[/tex]. To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.